Rule Of Boolean Algebra
7) A . A = A
Solution:
LHS = A . A
let A=0
LHS = 0.0
LHS = 0
LHS = RHS
8)
A . A̅ = 0
Solution:
LHS = A . A̅
let A=0
LHS = 0.1
LHS = 0
LHS = RHS
9)
A̅̅ = A
Solution:
LHS = A̅̅
let A=1
A̅ = 0
A̅̅ = 1
LHS = 1
LHS = RHS
10) A+AB = A
Solution:
LHS = A+AB
LHS = A(1+B)
LHS = A .1 ;(1+B=1)
LHS = A ;(A.1=A)
LHS = RHS
11)
A+ A̅B = A+B
Solution:
LHS = A+ A̅B
LHS = A+AB+ A̅B ; (A+AB=A)
LHS = A+B(A+ A̅) ;(A+ A̅=1)
LHS = A+B.1 ;(B.1=B)
LHS = A+B
LHS = RHS
12)
(A+B).(A+C) = A+BC
Solution:
LHS = (A+B).(A+C)
LHS = A.A+A.C+A.B+B.C ;(A.A=A)
LHS = A+ A.C+A.B+B.C
LHS = A.(1+C)+ A.B+B.C ;(1+C=1)
LHS = A+ A.B+B.C
LHS = A(1+B)+BC ;(1+B=1)
LHS = A+BC
LHS = RHS
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