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SQL Set Operators

SQL Set Operators   Traditional Set Operators: Union Compatibility:     Requirement for the traditional set operators.    Strong requirement.                         - Same number of columns.                         - Each corresponding column is compatible.                         - Positional correspondence.     Apply to similar tables by removing columns first. SQL UNION Example:           Example 1: Retrieve basic data about all university people.                     SELECT FacNo AS PerNo, FacFirstName                                      ...

Database Create Statements

University Database Create Statements:

 DROP TABLE Enrollment;

DROP TABLE offering;

DROP TABLE Student;

DROP TABLE Course;

DROP TABLE Faculty;

 

 

-------------------- Student ------------------------

 

CREATE TABLE Student (

stdNo char(11) not null,

stdFirstName varchar(30) not null,

stdLastName varchar(30) not null,

stdCity varchar(30) not null,

stdState char(2) not null,

stdZip char(10) not null,

stdMajor char(6),

stdClass char(2),

stdGPA decimal(3,2),

CONSTRAINT StudentPk PRIMARY KEY (StdNo) );

 

 

-------------------- Course ------------------------

 

CREATE TABLE Course(

CourseNo       char(6) not null,

crsDesc        varchar(50) not null,

CrsUnits       integer,

CONSTRAINT CoursePK PRIMARY KEY (CourseNo) );

 

 

-------------------- Faculty ---------------------

 

CREATE TABLE Faculty(

FacNo                  char(11) not null,

FacFirstName   varchar(30) not null,

FacLastName            varchar(30) not null,

FacCity                varchar(30) not null,

FacState               char(2) not null,

FacZipCode             char(10) not null,

FacRank                char(4),

FacHireDate            date,

FacSalary              decimal(10,2),

FacSupervisor  char(11),

FacDept                char(6),

CONSTRAINT FacultyPK PRIMARY KEY (FacNo) );

 

 

-------------------- Offering ------------------------

 

CREATE TABLE Offering(

OfferNo INTEGER not null,

CourseNo char(6) not null,

OffTerm char(6) not null,

OffYear INTEGER not null,

OffLocation varchar(30),

OffTime varchar(10),

FacNo char(11),

OffDays char(4),

CONSTRAINT OfferingPK PRIMARY KEY (OfferNo),

CONSTRAINT CourseFK FOREIGN KEY (CourseNo) REFERENCES Course (CourseNo),

CONSTRAINT FacultyFK FOREIGN KEY (FacNo) REFERENCES Faculty (FacNo) );

 

 

-------------------- Enrollment --------------------------

 

CREATE TABLE Enrollment (

OfferNo        INTEGER not null,

StdNo          char(11) not null,

EnrGrade       decimal(3,2),

CONSTRAINT EnrollmentPK PRIMARY KEY (OfferNo, StdNo),

CONSTRAINT OfferingFK FOREIGN KEY (OfferNo) REFERENCES Offering (OfferNo)

ON DELETE CASCADE,

CONSTRAINT StudentFK FOREIGN KEY (StdNo) REFERENCES Student (StdNo) ON DELETE CASCADE );


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Database Insert Statements



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SQL Set Operators

SQL Set Operators   Traditional Set Operators: Union Compatibility:     Requirement for the traditional set operators.    Strong requirement.                         - Same number of columns.                         - Each corresponding column is compatible.                         - Positional correspondence.     Apply to similar tables by removing columns first. SQL UNION Example:           Example 1: Retrieve basic data about all university people.                     SELECT FacNo AS PerNo, FacFirstName                                      ...
  d. Insert a new row in the Location table related to the Facility row in modification problem (c). The new row should have “Door” for the location name. Query Formulation + Result Snapshot Our Official Website :  Web Conquerors  (https://www.webconquerors.com/)  Want to get digital services?  Contact US Want to know about our services?  Our Services

Correction For ERD

 d. For each consistency error in Figure 1, you should identify the consistency rule violated and suggest possible resolutions of the error. The ERD has generic names to help will concentrate on finding diagram errors rather than focusing on the meaning of the diagram. Answer:                Entity6 is violation of the Primary key rule. As there are 3 attributes from within Entity6 that are marked as primary key. Entity6 also violates the Identifying relationship rule, as there is no foreign key in the Entity6 table to identify the item from Entity7. Since this a weak entity type, the cardinality must be 1:1, which it is not. Entity2 is a violation of the Identifying relationship rule due to it not being a weak entity type when there is an identifying relationship. Our Official Website :  Web Conquerors  (https://www.webconquerors.com/)  Want to get digital services?  Contact US Want to know about our services?  ...